Find Smallest Letter Greater Than Target
Easy
Binary Search
Problem
Given a sorted array of characters (wrapping around alphabetically) and a target, return the smallest character that compares strictly greater than target. Wraps around to the start.
Example 1
Input: letters=["c","f","j"], target="a"
Output: "c"
Example 2
Input: letters=["c","f","j"], target="j"
Output: "c"
Constraints
- 2 ≤ letters.length ≤ 10⁴
Approach — Binary Search
This is a Binary Search problem. The idea: repeatedly halve the search space, discarding the half that can't contain the answer. Work through the reference code below line by line, then re-derive it yourself in the editor — that's how the pattern sticks.
Complexity: O(log n) time.
Solution code
Python
class Solution:
def nextGreatestLetter(self, letters, target):
import bisect
i = bisect.bisect_right(letters, target)
return letters[i % len(letters)]
Java
class Solution {
public char nextGreatestLetter(char[] letters, char target) {
int lo = 0, hi = letters.length;
while (lo < hi) {
int m = lo + (hi - lo) / 2;
if (letters[m] <= target) lo = m + 1;
else hi = m;
}
return letters[lo % letters.length];
}
}
Practice it
Reading a solution isn't the same as being able to write it under pressure. Open this problem in the in-browser editor, hide the solution, and solve it from scratch — your code runs against real test cases instantly.
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