Power of Four
Easy
Bit ManipulationMath
Problem
Return true iff n is a power of four (1, 4, 16, 64, …).
Example 1
Input: n = 16
Output: true
Example 2
Input: n = 5
Output: false
Example 3
Input: n = 1
Output: true
Constraints
- −2³¹ ≤ n ≤ 2³¹−1
Approach — Core Patterns
This is a Core Patterns problem. The idea: pick the data structure best matched to the constraints and solve it in one clean pass. Work through the reference code below line by line, then re-derive it yourself in the editor — that's how the pattern sticks.
Complexity: see the walkthrough below.
Solution code
Python
class Solution:
def isPowerOfFour(self, n):
return n > 0 and (n & (n - 1)) == 0 and (n & 0x55555555) != 0
Java
class Solution {
public boolean isPowerOfFour(int n) {
return n > 0 && (n & (n - 1)) == 0 && (n & 0x55555555) != 0;
}
}
Practice it
Reading a solution isn't the same as being able to write it under pressure. Open this problem in the in-browser editor, hide the solution, and solve it from scratch — your code runs against real test cases instantly.
Solve Power of Four interactively → ← All solutions