Range Sum of BST
Easy
BSTTreeDFS
Problem
Given the root of a BST and integers low and high, return the sum of all node values in the inclusive range [low, high].
Example 1
Input: root = [10,5,15,3,7,null,18], low = 7, high = 15
Output: 32
Example 2
Input: root = [10,5,15,3,7,13,18,1,null,6], low = 6, high = 10
Output: 23
Constraints
- 1 ≤ nodes ≤ 2·10⁴
- 1 ≤ Node.val ≤ 10⁵
Approach — Tree Traversal
This is a Tree Traversal problem. The idea: traverse the tree — DFS recursively, or BFS level by level — and combine the results from each subtree. Work through the reference code below line by line, then re-derive it yourself in the editor — that's how the pattern sticks.
Complexity: O(n) time.
Solution code
Python
class Solution:
def rangeSumBST(self, root, low, high):
if not root:
return 0
if root.val < low:
return self.rangeSumBST(root.right, low, high)
if root.val > high:
return self.rangeSumBST(root.left, low, high)
return root.val + self.rangeSumBST(root.left, low, high) + self.rangeSumBST(root.right, low, high)
Java
class Solution {
public int rangeSumBST(TreeNode root, int low, int high) {
if (root == null) return 0;
if (root.val < low) return rangeSumBST(root.right, low, high);
if (root.val > high) return rangeSumBST(root.left, low, high);
return root.val + rangeSumBST(root.left, low, high) + rangeSumBST(root.right, low, high);
}
}
Practice it
Reading a solution isn't the same as being able to write it under pressure. Open this problem in the in-browser editor, hide the solution, and solve it from scratch — your code runs against real test cases instantly.
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