Tree Node Types
Medium
SQLCASEJOIN
Problem
Schema: Tree(id INT, parent_id INT). The root has parent_id IS NULL.
Label each node as Root / Inner / Leaf and return (id, type).
Example 1
Input: (1,NULL) (2,1) (3,1)
Output: (1, Root) (2, Leaf) (3, Leaf)
Constraints
- Tree may be empty.
Approach — Core Patterns
This is a Core Patterns problem. The idea: pick the data structure best matched to the constraints and solve it in one clean pass. Work through the reference code below line by line, then re-derive it yourself in the editor — that's how the pattern sticks.
Complexity: see the walkthrough below.
Solution code
SQL
SELECT t.id,
CASE
WHEN t.parent_id IS NULL THEN 'Root'
WHEN t.id NOT IN (SELECT parent_id FROM Tree WHERE parent_id IS NOT NULL) THEN 'Leaf'
ELSE 'Inner'
END AS type
FROM Tree t
ORDER BY t.id;
Practice it
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